Solve the system.
-$\left\{ \begin{array} { r }
x + y + z = 0 \
x - y + 2 z = - 2 \
2 x + y + z = - 4
\end{array} \right.$
A) $( 2 , - 4,2 )$
B) $( - 4,2,2 )$
C) $( 2,2 , - 4 )$
D) $\varnothing$

Question

Solve the system.
-$\left\{ \begin{array} { r } 
x + y + z = 0 \
x - y + 2 z = - 2 \
2 x + y + z = - 4
\end{array} \right.$
A) $( 2 , - 4,2 )$
B) $( - 4,2,2 )$
C) $( 2,2 , - 4 )$
D) $\varnothing$

Quizplus · Accepted Answer

By solving the system of equations using substitution or elimination, we find that the solution is $(-4, 2, 2)$.

Solve the System {x+y+z=0x−y+2z=−22x+y+z=−4\left\{ \begin{array} { r } x + y + z = 0 \\x - y + 2 z = - 2 \\2 x + y + z = - 4\end{array} \right.⎩⎨⎧​x+y+z=0x−y+2z=−22x+y+z=−4​

Solve the System $\left\{ \begin{array} { r } x + y + z = 0 \\x - y + 2 z = - 2 \\2 x + y + z = - 4\end{array} \right.$