Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l }
\frac { x } { 7 } + \frac { y } { 14 } = 1 \
\frac { x } { 2 } - \frac { y } { 4 } = 0
\end{array} \right.$
A) no solution
B) $\left( 7 , \frac { 7 } { 2 } \right)$
C) infinite number of solutions
D) $\left( \frac { 7 } { 2 } , 7 \right)$

Question

Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l } 
\frac { x } { 7 } + \frac { y } { 14 } = 1 \
\frac { x } { 2 } - \frac { y } { 4 } = 0
\end{array} \right.$
A) no solution
B) $\left( 7 , \frac { 7 } { 2 } \right)$
C) infinite number of solutions
D) $\left( \frac { 7 } { 2 } , 7 \right)$

Quizplus · Accepted Answer

The Answer of Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l } 
\frac { x } { 7 } + \frac { y } { 14 } = 1 \
\frac { x } { 2 } - \frac { y } { 4 } = 0
\end{array} \right.$
A) no solution
B) $\left( 7 , \frac { 7 } { 2 } \right)$
C) infinite number of solutions
D) $\left( \frac { 7 } { 2 } , 7 \right)$

Solve the System of Equations by the Addition Method {x7+y14=1x2−y4=0\left\{ \begin{array} { l } \frac { x } { 7 } + \frac { y } { 14 } = 1 \\\frac { x } { 2 } - \frac { y } { 4 } = 0\end{array} \right.{7x​+14y​=12x​−4y​=0​

Solve the System of Equations by the Addition Method $\left\{ \begin{array} { l } \frac { x } { 7 } + \frac { y } { 14 } = 1 \\\frac { x } { 2 } - \frac { y } { 4 } = 0\end{array} \right.$