Divide.
-$\left( x ^ { 2 } + 9 x + 20 \right) \div ( x + 4 )$
A) $x ^ { 2 } + 5$
B) $x - 16$
C) $x ^ { 3 } - 16$
D) $x + 5$

Name: Divide. -$\left( x ^ { 2 } + 9 x + 20 \right) \div ( x + 4 )$ A) $x ^ { 2 } + 5$ B) $x - 16$ C) $x ^ { 3 } - 16$ D) $x + 5$
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Question

Quizplus · Accepted Answer

The polynomial $x^2 + 9x + 20$ can be factored into $(x + 4)(x + 5)$. When dividing by $x + 4$, the $x + 4$ terms cancel out, leaving $x + 5$.

Divide - (x2+9x+20)÷(x+4)\left( x ^ { 2 } + 9 x + 20 \right) \div ( x + 4 )(x2+9x+20)÷(x+4)

Divide
- $\left( x ^ { 2 } + 9 x + 20 \right) \div ( x + 4 )$