Multiply using the FOIL method.
-$( 2 y - 9 ) ( 3 y + 10 )$
A) $6 y ^ { 2 } - 7 y - 90$
B) $6 y ^ { 2 } - 90$
C) $5 y ^ { 2 } + 1$
D) $6 y ^ { 2 } + 47 y - 90$

Question

Quizplus · Accepted Answer

The FOIL method involves multiplying the First terms, Outer terms, Inner terms, and Last terms of the binomials. For $(2y - 9)(3y + 10)$, the calculation is $2y \cdot 3y + 2y \cdot 10 - 9 \cdot 3y - 9 \cdot 10 = 6y^2 + 20y - 27y - 90 = 6y^2 - 7y - 90$.

Multiply Using the FOIL Method (2y−9)(3y+10)( 2 y - 9 ) ( 3 y + 10 )(2y−9)(3y+10)

Multiply Using the FOIL Method $( 2 y - 9 ) ( 3 y + 10 )$