Solve.
-An object is thrown upward from the top of a 160 -foot building with an initial velocity of 48 feet per second. The height $h$ of the object after $t$ seconds is given by the quadratic equation $h = - 16 t ^ { 2 } + 48 t + 160$. When will the object hit the ground?
A) $160 \mathrm { sec }$
B) $2 \mathrm { sec }$
C) $5 \mathrm { sec }$
D) $- 2 \mathrm { sec }$

Question

Quizplus · Accepted Answer

To find when the object hits the ground, set $h = 0$ and solve the quadratic equation $-16t^2 + 48t + 160 = 0$. Factoring or using the quadratic formula gives $t = 5$ seconds as the positive solution, indicating the object will hit the ground after 5 seconds. Negative time is not physically meaningful in this context.

Solve -An Object Is Thrown Upward from the Top of a 160

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-An Object Is Thrown Upward from the Top of a 160