Solve the equation.
-$\left( 2 x + \frac { 4 } { 5 } \right) \left( 4 x - \frac { 3 } { 7 } \right) = 0$
A) $- \frac { 2 } { 5 } , \frac { 3 } { 28 }$
B) $- \frac { 4 } { 5 } , \frac { 3 } { 7 }$
C) $- \frac { 2 } { 5 } , \frac { 3 } { 14 }$
D) $- \frac { 4 } { 5 } , \frac { 3 } { 28 }$

Question

Quizplus · Accepted Answer

For the equation $(2x + \frac{4}{5})(4x - \frac{3}{7}) = 0$ to hold, either $2x + \frac{4}{5} = 0$ or $4x - \frac{3}{7} = 0$. Solving these gives $x = -\frac{2}{5}$ and $x = \frac{3}{28}$, respectively.

Solve the Equation (2x+45)(4x−37)=0\left( 2 x + \frac { 4 } { 5 } \right) \left( 4 x - \frac { 3 } { 7 } \right) = 0(2x+54​)(4x−73​)=0

Solve the Equation $\left( 2 x + \frac { 4 } { 5 } \right) \left( 4 x - \frac { 3 } { 7 } \right) = 0$