Factor the binomial completely.
-$16 a ^ { 3 } - 9 a$
A) $a ( 16 a + 1 ) ( a - 9 )$
B) $a ( 4 a + 3 ) ( 4 a - 3 )$
C) $a ( 4 a - 3 ) ^ { 2 }$
D) $\left( 4 a ^ { 2 } + 3 \right) ( 4 a - 3 )$

Question

Quizplus · Accepted Answer

The binomial $16a^3 - 9a$ can be factored by first factoring out the greatest common factor (GCF), which is $a$, giving $a(16a^2 - 9)$. The expression inside the parentheses is a difference of squares, $16a^2 - 9 = (4a)^2 - 3^2$, which can be factored as $(4a + 3)(4a - 3)$. Therefore, the complete factorization is $a(4a + 3)(4a - 3)$.

Factor the Binomial Completely 16a3−9a16 a ^ { 3 } - 9 a16a3−9a

Factor the Binomial Completely $16 a ^ { 3 } - 9 a$