Factor completely.
-$12 x ^ { 4 } - 17 x ^ { 3 } + 6 x ^ { 2 }$
A) $\left( 12 x ^ { 2 } + 3 \right) \left( x ^ { 2 } + 2 \right)$
B) $x ( 4 x + 3 ) ( 3 x + 2 )$
C) $x ^ { 2 } ( 12 x - 1 ) ( x - 6 )$
D) $x ^ { 2 } ( 4 x - 3 ) ( 3 x - 2 )$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $x^2$, giving $x^2(12x^2 - 17x + 6)$. Then, factor the quadratic equation inside the parentheses to get $x^2(4x-3)(3x-2)$.

Factor Completely 12x4−17x3+6x212 x ^ { 4 } - 17 x ^ { 3 } + 6 x ^ { 2 }12x4−17x3+6x2

Factor Completely $12 x ^ { 4 } - 17 x ^ { 3 } + 6 x ^ { 2 }$