Factor completely.
-$4 y ^ { 2 } + 18 y - 10$
A) prime
B) $2 ( 2 y - 1 ) ( y + 5 )$
C) $2 ( 2 y + 1 ) ( y - 5 )$
D) $( 4 y - 2 ) ( y + 5 )$

Question

Quizplus · Accepted Answer

The expression can be factored by first taking out the greatest common factor, which is 2, resulting in $2(2y^2 + 9y - 5)$. Then, factor the quadratic $2y^2 + 9y - 5$ into $(2y - 1)(y + 5)$. Thus, the complete factorization is $2(2y - 1)(y + 5)$.

Factor Completely 4y2+18y−104 y ^ { 2 } + 18 y - 104y2+18y−10

Factor Completely $4 y ^ { 2 } + 18 y - 10$