Factor completely.
-$12 x ^ { 2 } + 17 x + 6$
A) $( 4 x - 3 ) ( 3 x - 2 )$
B) $( 12 x + 3 ) ( x + 2 )$
C) prime
D) $( 4 x + 3 ) ( 3 x + 2 )$

Question

Quizplus · Accepted Answer

To factor the quadratic equation $12x^2 + 17x + 6$, we look for two numbers that multiply to $12*6 = 72$ and add up to 17. Those numbers are 9 and 8. Rewriting the middle term (17x) as 9x + 8x gives us $12x^2 + 9x + 8x + 6$. Factoring by grouping, we get $3x(4x + 3) + 2(4x + 3)$, which simplifies to $(4x + 3)(3x + 2)$, matching option D.

Factor Completely 12x2+17x+612 x ^ { 2 } + 17 x + 612x2+17x+6

Factor Completely $12 x ^ { 2 } + 17 x + 6$