Find the least common denominator (LCD).
-$\frac { 6 } { x ^ { 2 } - 4 x } , \frac { 5 } { x ^ { 2 } - 2 x - 8 }$
A) $x ( x - 6 ) ( x + 2 )$
B) $( x - 6 ) ^ { 2 }$
C) $x ( x - 4 ) ( x + 2 )$
D) $x ( x - 6 ) ^ { 2 }$

Question

Quizplus · Accepted Answer

The least common denominator (LCD) is found by factoring each denominator and then taking the product of the highest power of all factors present. For $x^2 - 4x$, factor out an $x$ to get $x(x - 4)$. For $x^2 - 2x - 8$, factor to $(x - 4)(x + 2)$. The LCD must include each factor in its highest power present in any of the denominators, which gives us $x(x - 4)(x + 2)$.

Find the Least Common Denominator (LCD) 6x2−4x,5x2−2x−8\frac { 6 } { x ^ { 2 } - 4 x } , \frac { 5 } { x ^ { 2 } - 2 x - 8 }x2−4x6​,x2−2x−85​

Find the Least Common Denominator (LCD) $\frac { 6 } { x ^ { 2 } - 4 x } , \frac { 5 } { x ^ { 2 } - 2 x - 8 }$