Solve the equation or inequality.
-$| 3 x + 6 | \geq 2$
A) $\left[ - \frac { 4 } { 3 } , \infty \right]$
B) $\left[ - \frac { 8 } { 3 } , - \frac { 4 } { 3 } \right]$
C) $\left( - \frac { 8 } { 3 } , - \frac { 4 } { 3 } \right)$
D) $\left( - \infty , - \frac { 8 } { 3 } \right] \cup \left[ - \frac { 4 } { 3 } , \infty \right)$

Question

Quizplus · Accepted Answer

To solve $| 3x + 6 | \geq 2$, we consider two cases: $3x + 6 \geq 2$ and $3x + 6 \leq -2$. Solving the first gives $x \geq -\frac{4}{3}$ and the second gives $x \leq -\frac{8}{3}$. Combining these gives the solution set $\left( - \infty , - \frac { 8 } { 3 } \right] \cup \left[ - \frac { 4 } { 3 } , \infty \right)$.

Solve the Equation or Inequality ∣3x+6∣≥2| 3 x + 6 | \geq 2∣3x+6∣≥2

Solve the Equation or Inequality $| 3 x + 6 | \geq 2$