A discrete random variable x can assume five possible values: 2, 3, 5, 8, 10. Its probability distribution is shown below. Find the mean of the distribution. $\begin{array}{c|ccccc}
\mathrm{x} & 2 & 3 & 5 & 8 & 10 \
\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10
\end{array}$

A) $5.6$
B) $5.7$
C) $5.0$
D) $5.5$

Question

A discrete random variable x can assume five possible values: 2, 3, 5, 8, 10. Its probability distribution is shown below. Find the mean of the distribution. $\begin{array}{c|ccccc}
\mathrm{x} & 2 & 3 & 5 & 8 & 10 \
\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10
\end{array}$

A) $5.6$
B) $5.7$
C) $5.0$
D) $5.5$

Quizplus · Accepted Answer

The Answer of A discrete random variable x can assume five possible values: 2, 3, 5, 8, 10. Its probability distribution is shown below. Find the mean of the distribution. $\begin{array}{c|ccccc}
\mathrm{x} & 2 & 3 & 5 & 8 & 10 \
\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10
\end{array}$

A) $5.6$
B) $5.7$
C) $5.0$
D) $5.5$

A Discrete Random Variable X Can Assume Five Possible Values x235810p(x)0.100.200.300.300.10\begin{array}{c|ccccc}\mathrm{x} & 2 & 3 & 5 & 8 & 10 \\\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10\end{array}xp(x)​20.10​30.20​50.30​80.30​100.10​​

A Discrete Random Variable X Can Assume Five Possible Values $\begin{array}{c|ccccc}\mathrm{x} & 2 & 3 & 5 & 8 & 10 \\\hline \mathrm{p}(\mathrm{x}) & 0.10 & 0.20 & 0.30 & 0.30 & 0.10\end{array}$