Consider the following printout. HYPOTHESIS: MEAN $X = x$
$$X = \text { gpa }$$
SAMPLE MEAN OF $\mathrm { X } = 2.9528$
SAMPLE VARIANCE OF $X = 0.226933$
SAMPLE SIZE OF $X = 167$
HYPOTHESIZED VALUE $( \mathrm { x } ) = 3$
$$\begin{aligned}
\text { MEAN X - } x & = - 0.0472 \
z & = - 1.2804
\end{aligned}$$
Suppose a two-tailed test is desired. Find the $p$-value for the test.
A) $p = 0.2006$
B) $p = 0.8997$
C) $p = 0.7994$
D) $p = 0.1003$

Question

Quizplus · Accepted Answer

For a two-tailed test, the $p$-value is found by looking up the absolute value of the z-score in a standard normal distribution table and then doubling the result because it's two-tailed. A z-score of -1.2804 corresponds to a one-tailed $p$-value of approximately 0.1003. Doubling this for a two-tailed test gives $p = 0.2006$.

Consider the Following Printout X=xX = xX=x X= gpa X = \text { gpa }X= gpa

Consider the Following Printout $X = x$ $X = \text { gpa }$