A paired difference experiment produced the following results. $$n _ { d } = 40 , \bar { x } _ { 1 } = 18.4 , \bar { x } _ { 2 } = 19.7 , \bar { d } = - 1.3 , s _ { d } { } ^ { 2 } = 5$$
Perform the appropriate test to determine whether there is sufficient evidence to conclude that $\mu _ { 1 } ! \mu _ { 2 }$ using $\alpha = .10$.

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The Answer of A paired difference experiment produced the following results. $$n _ { d } = 40 , \bar { x } _ { 1 } = 18.4 , \bar { x } _ { 2 } = 19.7 , \bar { d } = - 1.3 , s _ { d } { } ^ { 2 } = 5$$
Perform the appropriate test to determine whether there is sufficient evidence to conclude that $\mu _ { 1 } ! \mu _ { 2 }$ using $\alpha = .10$.

A Paired Difference Experiment Produced the Following Results nd=40,xˉ1=18.4,xˉ2=19.7,dˉ=−1.3,sd2=5n _ { d } = 40 , \bar { x } _ { 1 } = 18.4 , \bar { x } _ { 2 } = 19.7 , \bar { d } = - 1.3 , s _ { d } { } ^ { 2 } = 5nd​=40,xˉ1​=18.4,xˉ2​=19.7,dˉ=−1.3,sd​2=5

A Paired Difference Experiment Produced the Following Results $n _ { d } = 40 , \bar { x } _ { 1 } = 18.4 , \bar { x } _ { 2 } = 19.7 , \bar { d } = - 1.3 , s _ { d } { } ^ { 2 } = 5$