Solve the problem.
-The length of the diagonal of a rectangle is given by $D = \sqrt { L ^ { 2 } + W ^ { 2 } }$ where $L$ and $W$ are the length and width of the rectangle. What is the length of the diagonal, D, of a rectangle that is 83 inches long and 22 inches wide? Round your answer to the nearest tenth of an inch, if necessary.
A) $80 \mathrm { in }$.
B) $10.2 \mathrm { in }$.
C) $42.7 \mathrm { in }$.
D) $85.9 \mathrm { in }$.

Question

Quizplus · Accepted Answer

Using the formula $D = \sqrt { L ^ { 2 } + W ^ { 2 } }$, with $L = 83$ inches and $W = 22$ inches, we get $D = \sqrt { 83 ^ { 2 } + 22 ^ { 2 } } = \sqrt { 6889 + 484 } = \sqrt { 7373 }$ inches, which rounds to approximately $85.9$ inches.

Solve the Problem D=L2+W2D = \sqrt { L ^ { 2 } + W ^ { 2 } }D=L2+W2​

Solve the Problem $D = \sqrt { L ^ { 2 } + W ^ { 2 } }$