Factor the trinomial, if possible.
-$$9 z ^ { 2 } + 6 z - 8$$
A) $( 3 z + 4 ) ( 3 z - 2 )$
B) $( 3 z - 4 ) ( 3 z + 2 )$
C) $( 9 z + 1 ) ( z - 8 )$
D) $( 9 z + 4 ) ( z - 2 )$

Name: Factor the trinomial, if possible. -\[9 z ^ { 2 } + 6 z - 8\] A) $( 3 z + 4 ) ( 3 z - 2 )$ B) $( 3 z - 4 ) ( 3 z + 2 )$ C) $( 9 z + 1 ) ( z - 8 )$ D) $( 9 z + 4 ) ( z - 2 )$
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Question

Quizplus · Accepted Answer

The correct factorization of $9z^2 + 6z - 8$ is $(3z + 4)(3z - 2)$, which multiplies out to $9z^2 - 6z + 12z - 8$, simplifying to $9z^2 + 6z - 8$.

Factor the Trinomial, If Possible 9z2+6z−89 z ^ { 2 } + 6 z - 89z2+6z−8

Factor the Trinomial, If Possible $9 z ^ { 2 } + 6 z - 8$