Divide.
-$$\frac { x ^ { 4 } + 3 x ^ { 2 } + 8 } { x ^ { 2 } + 1 }$$
A) $x ^ { 2 } + 2 x + 6$
B) $x ^ { 2 } + 2$
C) $x ^ { 2 } + 2 x + \frac { 5 } { 2 }$
D) $x ^ { 2 } + 2 + \frac { 6 } { x ^ { 2 } + 1 }$

Question

Quizplus · Accepted Answer

When dividing polynomials, the quotient is $x^2 + 2$ and the remainder is 6, so the expression is $x^2 + 2 + \frac{6}{x^2 + 1}$.

Divide - x4+3x2+8x2+1\frac { x ^ { 4 } + 3 x ^ { 2 } + 8 } { x ^ { 2 } + 1 }x2+1x4+3x2+8​

Divide
- $\frac { x ^ { 4 } + 3 x ^ { 2 } + 8 } { x ^ { 2 } + 1 }$