Solve the problem.
-The length of a rectangle is 10 inches more than its width. If 5 inches are taken from the length and added to the width, the figure becomes a square with an area of 121 square inches. What are the
Dimensions of the original figure?
A) 1 in. by 11 in.
B) 6 in. by $16 \mathrm { in } .$
C) 6 in. by $11 \mathrm { in } .$
D) 11 in. by 11 in.

Question

Solve the problem.
-The length of a rectangle is 10 inches more than its width. If 5 inches are taken from the length and added to the width, the figure becomes a square with an area of 121 square inches. What are the
Dimensions of the original figure? 
A) 1 in. by 11 in.
B) 6 in. by $16 \mathrm { in } .$
C) 6 in. by $11 \mathrm { in } .$
D) 11 in. by 11 in.

Quizplus · Accepted Answer

The square's side length is the square root of its area, which is $\sqrt{121} = 11$ inches. Since 5 inches were added to the width and subtracted from the length to form the square, the original width was $11 - 5 = 6$ inches, and the original length was $11 + 5 = 16$ inches. Therefore, the dimensions of the original rectangle are 6 inches by 16 inches.

Solve the Problem 16in.16 \mathrm { in } .16in. C) 6 In By Problem

Solve the Problem $16 \mathrm { in } .$ C) 6 In By Problem