Identify the type of graph.
-$$( x + 6 ) ^ { 2 } + ( y - 4 ) ^ { 2 } + 12 = 0$$
A) The graph is the point $( - 6,4 )$.
B) The equation has no graph.
C) The graph is a circle with center $( - 6,4 )$.
D) The graph is an ellipse with center $( 6 , - 4 )$.

Question

Quizplus · Accepted Answer

The equation is supposed to represent a circle, but the constant term on the right side makes the radius squared negative ($12 = 0$ is impossible), meaning there's no real graph for this equation.

Identify the Type of Graph (x+6)2+(y−4)2+12=0( x + 6 ) ^ { 2 } + ( y - 4 ) ^ { 2 } + 12 = 0(x+6)2+(y−4)2+12=0

Identify the Type of Graph $( x + 6 ) ^ { 2 } + ( y - 4 ) ^ { 2 } + 12 = 0$