Fill in the blanks to complete the statement. The graph of $\mathrm { P } ( \mathrm { x } ) = - 0.1 ( \mathrm { x } - 4 ) ^ { 2 }$ is a parabola with ــــــــــ$x$-intercept(s). Its vertex is theــــــــــــــ point of the graph and has coordinatesـــــــــــــــــــ
A) no; maximum (or highest); $( - 0.1,4 )$
B) two; maximum (or highest); $( 4,0 )$
C) one; minimum (or lowest); $( 4,0 )$
D) one; maximum (or highest); $( 4,0 )$

Question

Quizplus · Accepted Answer

The graph of a parabola in the form $P(x) = a(x - h)^2 + k$ has its vertex at the point $(h, k)$. In this case, the vertex is at $(4, 0)$. The parabola opens downward because the coefficient of $x^2$ is negative. Therefore, the vertex is the maximum point of the graph. Since the parabola opens downward, it has no $x$-intercepts.

Fill in the Blanks to Complete the Statement P(x)=−0.1(x−4)2\mathrm { P } ( \mathrm { x } ) = - 0.1 ( \mathrm { x } - 4 ) ^ { 2 }P(x)=−0.1(x−4)2

Fill in the Blanks to Complete the Statement $\mathrm { P } ( \mathrm { x } ) = - 0.1 ( \mathrm { x } - 4 ) ^ { 2 }$