Answer the question.
-Bruce agrees to go to work for Jim at a rate of $3 \notin$ for the first day, $6 \$$ for the second day, $12 \$$ for the third day, $24 \uparrow$ for the fourth day, and so on. What will Bruce's daily pay be on day 10 , and how much total wages will he have earned at the end of that day?
A) Pay on day $10 = \$ 30.72$; Total pay through day $10 = \$ 15.33$
B) Pay on day $10 = \$ 5.12$; Total pay through day $10 = \$ 10.23$
C) Pay on day $10 = \$ 15.36$; Total pay through day $10 = \$ 30.69$
D) Pay on day $10 = \$ 30.72$; Total pay through day $10 = \$ 30.69$

Question

Quizplus · Accepted Answer

Bruce's pay doubles each day, starting from $3 on the first day. By day 10, his pay will be $3 \times 2^9 = \$ 15.36$. The total pay is the sum of a geometric series: $3 \times (2^{10} - 1) = \$ 30.69$.

Answer the Question 3∉3 \notin3∈/ For the First Day 6$6 \$6$ For the Second Day

Answer the Question $3 \notin$ For the First Day $6 \$$ For the Second Day