Give a rule for the piecewise-defined function. Then give the domain and range.
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A) $f ( x ) = \left\{ \begin{array} { l l } 2 x & \text { if } x \leq 1 \ x + 1 & \text { if } x 1 \end{array} ; \right.$ Domain: $( - \infty , \infty )$, Range: $( - \infty , \infty )$
B) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \ x + 1 & \text { if } x 1 \end{array} \right.$; Domain: $( - \infty , \infty )$, Range: $( - \infty , \infty )$
C) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \ x + 2 & \text { if } x 1 \end{array} \right.$; Domain: $( - \infty , 2 ) \cup ( 2 , \infty )$, Range: $( - \infty , \infty )$
D) $f ( x ) = \left\{ \begin{array} { l l } - x & \text { if } x \leq 1 \ 2 x + 1 & \text { if } x 1 \end{array} ; \right.$ Domain: $( - \infty , \infty )$, Range: $( - \infty , 2 ) \cup ( 2 , \infty )$

Question

Give a rule for the piecewise-defined function. Then give the domain and range.
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A) $f ( x ) = \left\{ \begin{array} { l l } 2 x & \text { if } x \leq 1 \ x + 1 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( - \infty , \infty )$, Range: $( - \infty , \infty )$ 
B) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \ x + 1 & \text { if } x > 1 \end{array} \right.$; Domain: $( - \infty , \infty )$, Range: $( - \infty , \infty )$ 
C) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \ x + 2 & \text { if } x > 1 \end{array} \right.$; Domain: $( - \infty , 2 ) \cup ( 2 , \infty )$, Range: $( - \infty , \infty )$ 
D) $f ( x ) = \left\{ \begin{array} { l l } - x & \text { if } x \leq 1 \ 2 x + 1 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( - \infty , \infty )$, Range: $( - \infty , 2 ) \cup ( 2 , \infty )$

Quizplus · Accepted Answer

The Answer of Give a rule for the piecewise-defined function. Then give the domain and range.
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A) $f ( x ) = \left\{ \begin{array} { l l } 2 x & \text { if } x \leq 1 \ x + 1 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( - \infty , \infty )$, Range: $( - \infty , \infty )$ 
B) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \ x + 1 & \text { if } x > 1 \end{array} \right.$; Domain: $( - \infty , \infty )$, Range: $( - \infty , \infty )$ 
C) $f ( x ) = \left\{ \begin{array} { l l } - 2 x & \text { if } x \leq 1 \ x + 2 & \text { if } x > 1 \end{array} \right.$; Domain: $( - \infty , 2 ) \cup ( 2 , \infty )$, Range: $( - \infty , \infty )$ 
D) $f ( x ) = \left\{ \begin{array} { l l } - x & \text { if } x \leq 1 \ 2 x + 1 & \text { if } x > 1 \end{array} ; \right.$ Domain: $( - \infty , \infty )$, Range: $( - \infty , 2 ) \cup ( 2 , \infty )$

Give a Rule for the Piecewise-Defined Function f(x)={2x if x≤1x+1 if x>1;f ( x ) = \left\{ \begin{array} { l l } 2 x & \text { if } x \leq 1 \\ x + 1 & \text { if } x > 1 \end{array} ; \right.f(x)={2xx+1​ if x≤1 if x>1​;

Give a Rule for the Piecewise-Defined Function $f ( x ) = \left\{ \begin{array} { l l } 2 x & \text { if } x \leq 1 \\ x + 1 & \text { if } x > 1 \end{array} ; \right.$