An equation that defines y as a function of x is given. Solve for y in terms of x, and replace y with the function notation
f(x).
-$$x + 6 y = 8$$
A) $f ( x ) = \frac { 1 } { 6 } x + \frac { 4 } { 3 }$
B) $f ( x ) = - x + \frac { 4 } { 3 }$
C) $f ( x ) = - \frac { 1 } { 6 } x + \frac { 4 } { 3 }$
D) $f ( x ) = 6 x - 8$

Question

Quizplus · Accepted Answer

To solve for $y$ in terms of $x$, we first isolate $y$ on one side of the equation: $x + 6y = 8$ becomes $6y = 8 - x$, which simplifies to $y = \frac{8 - x}{6}$. This can be further simplified to $y = -\frac{1}{6}x + \frac{4}{3}$, which corresponds to option C when replacing $y$ with $f(x)$.

An Equation That Defines Y as a Function of X x+6y=8x + 6 y = 8x+6y=8

An Equation That Defines Y as a Function of X $x + 6 y = 8$