Give the domain and range of the relation.
-$$y = \sqrt { 2 x - 7 }$$
A) domain: $\left[ \frac { 7 } { 2 } , \infty \right)$; range: $( - \infty , \infty )$
B) domain: $\left( \frac { 7 } { 2 } , \infty \right)$; range: $[ 0 , \infty )$
C) domain: $( - \infty , \infty )$; range: $\left[ \frac { 7 } { 2 } , \infty \right)$
D) domain: $\left[ \frac { 7 } { 2 } , \infty \right\}$; range: $[ 0 , \infty )$

Question

Quizplus · Accepted Answer

The square root function $\sqrt{2x - 7}$ requires the argument $2x - 7$ to be non-negative, so $2x - 7 \geq 0$, which gives $x \geq \frac{7}{2}$. This defines the domain as $\left[\frac{7}{2}, \infty\right)$. Since square roots are always non-negative, the range is $[0, \infty)$.

Give the Domain and Range of the Relation y=2x−7y = \sqrt { 2 x - 7 }y=2x−7​

Give the Domain and Range of the Relation $y = \sqrt { 2 x - 7 }$