Solve the problem.
-Find the center-radius form of the equation of a circle with center $( 3,8 )$ and tangent to the $x$-axis.
A) $( x + 3 ) ^ { 2 } + ( y + 8 ) ^ { 2 } = 64$
B) $( x + 3 ) ^ { 2 } + ( y + 8 ) ^ { 2 } = 9$
C) $( x - 3 ) ^ { 2 } + ( y - 8 ) ^ { 2 } = 9$
D) $( x - 3 ) ^ { 2 } + ( y - 8 ) ^ { 2 } = 64$

Question

Quizplus · Accepted Answer

The center-radius form of a circle is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. Given the center $(3, 8)$ and the fact that the circle is tangent to the $x$-axis, the distance from the center to the $x$-axis (which is 8 units) is the radius. Thus, $r = 8$, and the equation becomes $(x - 3)^2 + (y - 8)^2 = 64$.

Solve the Problem (3,8)( 3,8 )(3,8) And Tangent to The xxx -Axis A)

Solve the Problem $( 3,8 )$ And Tangent to The $x$ -Axis
A)