Find the center-radius form of the equation of the circle.
-center $( 0,2 )$, radius $\sqrt { 19 }$
A) $x ^ { 2 } + ( y + 2 ) ^ { 2 } = 19$
B) $( x - 2 ) ^ { 2 } + y ^ { 2 } = 361$
C) $x ^ { 2 } + ( y - 2 ) ^ { 2 } = 19$
D) $( x + 2 ) ^ { 2 } + y ^ { 2 } = 361$

Question

Quizplus · Accepted Answer

The center-radius form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. For a center at $(0, 2)$ and radius $\sqrt{19}$, the equation is $x^2 + (y - 2)^2 = 19$.

Find the Center-Radius Form of the Equation of the Circle (0,2)( 0,2 )(0,2)

Find the Center-Radius Form of the Equation of the Circle $( 0,2 )$