Find the center-radius form of the equation of the circle.
-center $( 0 , - 10 )$, radius 6
A) $x ^ { 2 } + ( y + 10 ) ^ { 2 } = 36$
B) $( x - 10 ) ^ { 2 } + y ^ { 2 } = 36$
C) $( x + 10 ) ^ { 2 } + y ^ { 2 } = 36$
D) $x ^ { 2 } + ( y - 10 ) ^ { 2 } = 6$

Question

Quizplus · Accepted Answer

The equation of a circle in center-radius form is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. For a center at $(0, -10)$ and radius $6$, the equation becomes $x^2 + (y + 10)^2 = 36$.

Find the Center-Radius Form of the Equation of the Circle (0,−10)( 0 , - 10 )(0,−10)

Find the Center-Radius Form of the Equation of the Circle $( 0 , - 10 )$