For the points P and Q, find the distance d(P, Q).
-$$\mathrm { P } ( 7 , - 1 ) , \mathrm { Q } ( - 5 , - 7 )$$
A) 108
B) $108 \sqrt { 3 }$
C) 6
D) $6 \sqrt { 5 }$

Question

Quizplus · Accepted Answer

The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ in a plane is given by the formula $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Applying this formula to points P(7, -1) and Q(-5, -7), we get $\sqrt{(-5 - 7)^2 + (-7 + 1)^2} = \sqrt{(-12)^2 + (-6)^2} = \sqrt{144 + 36} = \sqrt{180} = 6\sqrt{5}$.

For the Points P and Q, Find the Distance D(P P(7,−1),Q(−5,−7)\mathrm { P } ( 7 , - 1 ) , \mathrm { Q } ( - 5 , - 7 )P(7,−1),Q(−5,−7)

For the Points P and Q, Find the Distance D(P $\mathrm { P } ( 7 , - 1 ) , \mathrm { Q } ( - 5 , - 7 )$