Solve the problem.
-The pitch $P$ of a musical tone varies inversely as its wavelength $W$. One tone has a pitch of 202 vibrations per second and a wavelength of $2.7 \mathrm { ft }$. Find the wavelength of another tone that a pitch of 481 vibrations per second. Round to the nearest tenth.
A) $35,985.9 \mathrm { ft }$
B) $1.1 \mathrm { ft }$
C) $0 \mathrm { ft }$
D) $0.9 \mathrm { ft }$

Question

Quizplus · Accepted Answer

Since pitch $P$ varies inversely as its wavelength $W$, we can write the relationship as $P = k/W$, where $k$ is a constant. For the first tone, $P = 202$ and $W = 2.7$, so we can solve for $k$ as $k = P \times W = 202 \times 2.7$. For the second tone with $P = 481$, we use the same constant $k$ to find the new wavelength $W$, leading to $W = k / P$. Substituting the values and solving gives a wavelength of approximately $1.1 \mathrm { ft }$.

Solve the Problem PPP Of a Musical Tone Varies Inversely as Its Wavelength

Solve the Problem $P$ Of a Musical Tone Varies Inversely as Its Wavelength