Give the equatiosn of any horizontal asymptotes.
-$$f ( x ) = \frac { x ^ { 2 } + 2 } { x ^ { 2 } - 2 }$$
A) $y = 0$
B) none
C) $y = 1$
D) $y = 2$

Question

Quizplus · Accepted Answer

For rational functions, if the degrees of the numerator and denominator are the same, the horizontal asymptote is found by dividing the leading coefficients. Here, both the numerator and denominator are degree 2, and the leading coefficients are both 1, so the horizontal asymptote is $y = \frac{1}{1} = 1$.

Give the Equatiosn of Any Horizontal Asymptotes f(x)=x2+2x2−2f ( x ) = \frac { x ^ { 2 } + 2 } { x ^ { 2 } - 2 }f(x)=x2−2x2+2​

Give the Equatiosn of Any Horizontal Asymptotes $f ( x ) = \frac { x ^ { 2 } + 2 } { x ^ { 2 } - 2 }$