Use Descartesʹ Rule of Signs to determine the possible number of positive real zeros and the possible negative real zeros for the function.
-$$- 4 x ^ { 4 } + 3 x ^ { 3 } - 7 x ^ { 2 } + 6 x - 9 = 0$$
A) Positive $( 2,0 )$, negative $( 4,2,0 )$
B) Positive $( 2,0 )$, negative $( 2,0 )$
C) Positive $( 4,2,0 )$, negative $( 0 )$
D) Positive $( 4,2,0 )$, negative $( 4,2,0 )$

Question

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The Answer of Use Descartesʹ Rule of Signs to determine the possible number of positive real zeros and the possible negative real zeros for the function.
-$$- 4 x ^ { 4 } + 3 x ^ { 3 } - 7 x ^ { 2 } + 6 x - 9 = 0$$
A) Positive $( 2,0 )$, negative $( 4,2,0 )$
B) Positive $( 2,0 )$, negative $( 2,0 )$
C) Positive $( 4,2,0 )$, negative $( 0 )$
D) Positive $( 4,2,0 )$, negative $( 4,2,0 )$

Use Descartesʹ Rule of Signs to Determine the Possible Number −4x4+3x3−7x2+6x−9=0- 4 x ^ { 4 } + 3 x ^ { 3 } - 7 x ^ { 2 } + 6 x - 9 = 0−4x4+3x3−7x2+6x−9=0

Use Descartesʹ Rule of Signs to Determine the Possible Number $- 4 x ^ { 4 } + 3 x ^ { 3 } - 7 x ^ { 2 } + 6 x - 9 = 0$