Solve the problem.
-The decay of 667 mg of an isotope is given by A(t)= 667e-0.015t, where t is time in years since the initial amount of 667 mg was present. Find the amount (to the nearest milligram) left after 24
Years.
A) 657
B) 458
C) 233
D) 465

Question

Quizplus · Accepted Answer

To find the amount left after 24 years, substitute $t = 24$ into the given formula: $A(24) = 667e^{-0.015 \times 24}$. Calculating this gives approximately 465 mg.

Solve the Problem. -The Decay of 667 Mg of an Isotope Is Given