Solve the problem.
-The grade resistance $\mathrm { F }$ of a car traveling up or down a hill is modeled by the equation $\mathrm { F } = \mathrm { W } \sin \theta$ , where $W$ is the weight of the car and $\theta$ is the angle of the hill's grade $( \theta > 0$ for uphill travel, $\theta < 0$ for downhill travel) . What is the grade resistance (to the nearest pound) of a 2750 -lb car on a level road $\left( \theta = 0 ^ { \circ } \right)$ ?

Question

Solve the problem.
-The grade resistance $\mathrm { F }$ of a car traveling up or down a hill is modeled by the equation $\mathrm { F } = \mathrm { W } \sin \theta$, where $W$ is the weight of the car and $\theta$ is the angle of the hill's grade $( \theta > 0$ for uphill travel, $\theta < 0$ for downhill travel). What is the grade resistance (to the nearest pound) of a 2750 -lb car on a level road $\left( \theta = 0 ^ { \circ } \right)$ ?
A) $- 2750 \mathrm { lb }$
B) $0 \mathrm { lb }$
C) $2750 \mathrm { lb }$
D) undefined

Quizplus · Accepted Answer

The grade resistance on a level road ($\theta = 0^\circ$) is $0 \, \mathrm{lb}$ because $\sin(0^\circ) = 0$, making the grade resistance $F = 2750 \times 0 = 0 \, \mathrm{lb}$.

Solve the Problem F\mathrm { F }F Of a Car Traveling Up or Down a Hill Is

Solve the Problem $\mathrm { F }$ Of a Car Traveling Up or Down a Hill Is