Solve the problem.
-A surveyor recording data for a new subdivision measured an angle as $16.82 ^ { \circ }$. The next day, a different surveyor measured the same angle as $16 ^ { \circ } 31 ^ { \prime }$. Find the difference between these measurements (i) to the nearest minute and (ii) to the nearest hundredth of a degree.
A) (i) $80 ^ { \prime }$
(ii) $1.34 ^ { \circ }$

B) (i) $18 ^ { \prime }$
(ii) $0.30 ^ { \circ }$

C) (i) $51 ^ { \prime }$
(ii) $0.51 ^ { \circ }$

D) (i) $43 ^ { \prime }$
(ii) $0.48 ^ { \circ }$

Question

Solve the problem.
-A surveyor recording data for a new subdivision measured an angle as $16.82 ^ { \circ }$. The next day, a different surveyor measured the same angle as $16 ^ { \circ } 31 ^ { \prime }$. Find the difference between these measurements (i) to the nearest minute and (ii) to the nearest hundredth of a degree.
A) (i) $80 ^ { \prime }$
(ii) $1.34 ^ { \circ }$

B) (i) $18 ^ { \prime }$
(ii) $0.30 ^ { \circ }$

C) (i) $51 ^ { \prime }$
(ii) $0.51 ^ { \circ }$

D) (i) $43 ^ { \prime }$
(ii) $0.48 ^ { \circ }$

Quizplus · Accepted Answer

First, convert the first measurement to degrees and minutes: $16.82^\circ = 16^\circ + 0.82 \times 60' = 16^\circ 49.2'$. The difference between $16^\circ 49.2'$ and $16^\circ 31'$ is $18.2'$, which rounds to $18'$ to the nearest minute. For the nearest hundredth of a degree, $18'$ is $18/60 = 0.3^\circ$.

Solve the Problem 16.82∘16.82 ^ { \circ }16.82∘ the Next Day, a Different Surveyor Measured the Same

Solve the Problem $16.82 ^ { \circ }$ the Next Day, a Different Surveyor Measured the Same