Find the exact value of s in the given interval that has the given circular function value.
-$$\left[ \pi , \frac { 3 \pi } { 2 } \right] ; \sin \mathrm { s } = - \frac { \sqrt { 3 } } { 2 }$$
A) $\mathrm { s } = \frac { 5 \pi } { 4 }$
B) $s = \frac { 4 \pi } { 3 }$
C) $s = \frac { 7 \pi } { 6 }$
D) $s = \frac { \pi } { 3 }$

Question

Quizplus · Accepted Answer

The sine function equals $-\frac{\sqrt{3}}{2}$ at $s = \frac{4\pi}{3}$, which is in the given interval $\left[\pi, \frac{3\pi}{2}\right]$.

Find the Exact Value of S in the Given Interval [π,3π2];sin⁡s=−32\left[ \pi , \frac { 3 \pi } { 2 } \right] ; \sin \mathrm { s } = - \frac { \sqrt { 3 } } { 2 }[π,23π​];sins=−23​​

Find the Exact Value of S in the Given Interval $\left[ \pi , \frac { 3 \pi } { 2 } \right] ; \sin \mathrm { s } = - \frac { \sqrt { 3 } } { 2 }$