Provide an appropriate response.
-Explain what is wrong with the following solution for the equation $\sin 2 \theta = \sqrt { 3 }$ in the interval $[ 0,2 \pi )$.
$$\sin 2 \theta = \sqrt { 3 }$$
$\sin \theta = \frac { \sqrt { 3 } } { 2 }$
$$\theta = \frac { \pi } { 3 } \text { or } \theta = \frac { 2 \pi } { 3 }$$

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The Answer of Provide an appropriate response.
-Explain what is wrong with the following solution for the equation $\sin 2 \theta = \sqrt { 3 }$ in the interval $[ 0,2 \pi )$.
$$\sin 2 \theta = \sqrt { 3 }$$
$\sin \theta = \frac { \sqrt { 3 } } { 2 }$
$$\theta = \frac { \pi } { 3 } \text { or } \theta = \frac { 2 \pi } { 3 }$$

Provide an Appropriate Response sin⁡2θ=3\sin 2 \theta = \sqrt { 3 }sin2θ=3​

Provide an Appropriate Response $\sin 2 \theta = \sqrt { 3 }$