Perform the indicated operations and simplify the result so there are no quotients.
-$\tan ^ { 2 } \theta - 3 \sin \theta \tan \theta \sec \theta$
A) $\sin \theta \tan \theta$
B) $1 + \cot \theta$
C) $\sec \theta \csc \theta$
D) $- 2 \tan ^ { 2 } \theta$

Question

Quizplus · Accepted Answer

The expression $\tan^2 \theta - 3 \sin \theta \tan \theta \sec \theta$ simplifies to $-2 \tan^2 \theta$ by substituting $\tan \theta = \frac{\sin \theta}{\cos \theta}$ and $\sec \theta = \frac{1}{\cos \theta}$, then simplifying the terms.

Perform the Indicated Operations and Simplify the Result So There tan⁡2θ−3sin⁡θtan⁡θsec⁡θ\tan ^ { 2 } \theta - 3 \sin \theta \tan \theta \sec \thetatan2θ−3sinθtanθsecθ

Perform the Indicated Operations and Simplify the Result So There $\tan ^ { 2 } \theta - 3 \sin \theta \tan \theta \sec \theta$