Solve the problem.
-A force of $35 \mathrm { lb }$ is required to hold a $78 \mathrm { lb }$ toolbox on an incline. What angle does the incline make with the horizontal?
A) $77.0 ^ { \circ }$
B) $26.7 ^ { \circ }$
C) $63.3 ^ { \circ }$
D) $13.0 ^ { \circ }$

Question

Quizplus · Accepted Answer

The angle can be found using the formula for the component of the weight parallel to the incline, which is $F = W \sin(\theta)$, where $F$ is the force parallel to the incline (35 lb), $W$ is the weight of the object (78 lb), and $\theta$ is the angle of the incline. Solving for $\theta$, we get $\theta = \sin^{-1}(F/W) = \sin^{-1}(35/78) \approx 26.7^\circ$.

Solve the Problem 35lb35 \mathrm { lb }35lb Is Required to Hold A

Solve the Problem $35 \mathrm { lb }$ Is Required to Hold A