Solve the problem.
-A hot-air balloon is rising vertically $13 \mathrm { ft } / \mathrm { sec }$ while the wind is blowing horizontally at $6 \mathrm { ft } / \mathrm { sec }$. Find the angle that the balloon makes with the horizontal.
A) $65.2 ^ { \circ }$
B) $51.3 ^ { \circ }$
C) $24.8 ^ { \circ }$
D) $47.4 ^ { \circ }$

Question

Quizplus · Accepted Answer

The angle $\theta$ that the balloon makes with the horizontal can be found using the tangent function, where $\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{13}{6}$. Solving for $\theta$ gives $\theta \approx 65.2^\circ$.

Solve the Problem 13ft/sec13 \mathrm { ft } / \mathrm { sec }13ft/sec

Solve the Problem $13 \mathrm { ft } / \mathrm { sec }$