Find the magnitude and direction angle (to the nearest tenth) for each vector. Give the measure of the direction angle as an angle in [0,360°].
-$$\langle 0 , - 6 \rangle$$
A) $6 ; 90 ^ { \circ }$
B) $36 ; 270 ^ { \circ }$
C) $6 ; 270 ^ { \circ }$
D) $6 ; 180 ^ { \circ }$

Question

Quizplus · Accepted Answer

The magnitude of the vector $\langle 0 , - 6 \rangle$ is $6$, calculated using the formula $\sqrt{0^2 + (-6)^2} = 6$. The direction angle is $270^\circ$ because the vector points directly downward on the Cartesian plane, which corresponds to the positive y-axis direction in the negative direction.

Find the Magnitude and Direction Angle (To the Nearest Tenth) ⟨0,−6⟩\langle 0 , - 6 \rangle⟨0,−6⟩

Find the Magnitude and Direction Angle (To the Nearest Tenth) $\langle 0 , - 6 \rangle$