Find the magnitude and direction angle (to the nearest tenth) for each vector. Give the measure of the direction angle as an angle in [0,360°].
-$\langle 6,6 \rangle$
A) $12 ; 45 ^ { \circ }$
B) $6 ; 225 ^ { \circ }$
C) $6 \sqrt { 2 } ; 45 ^ { \circ }$
D) $6 \sqrt { 2 } ; 225 ^ { \circ }$

Question

Quizplus · Accepted Answer

The magnitude of the vector $\langle 6,6 \rangle$ is found using the Pythagorean theorem, resulting in $6\sqrt{2}$. The direction angle, measured from the positive x-axis, is $45^\circ$ because the vector has equal x and y components, placing it in the first quadrant.

Find the Magnitude and Direction Angle (To the Nearest Tenth) ⟨6,6⟩\langle 6,6 \rangle⟨6,6⟩

Find the Magnitude and Direction Angle (To the Nearest Tenth) $\langle 6,6 \rangle$