Find the matrix product when possible.
-$\left[ \begin{array} { r r } 3 & - 2 \ 6 & 0 \end{array} \right] \left[ \begin{array} { r r } 0 & - 2 \ 2 & 6 \end{array} \right]$
A)
$\left[\begin{array}{rr}
-4 & -18 \
0 & -12
\end{array}\right]$
B)
$\left[\begin{array}{rr}
-12 & 0 \
42 & -4
\end{array}\right]$
C)
$\left[\begin{array}{rr}
0 & 4 \
12 & 0
\end{array}\right]$
D)
$\left[\begin{array}{rr}
-18 & -4 \
-12 & 0
\end{array}\right]$

Question

Quizplus · Accepted Answer

To find the product of two matrices, we multiply each row of the first matrix by each column of the second matrix and sum the products. For the given matrices:1. For the first element (top left), $3*0 + (-2)*2 = 0 - 4 = -4$.2. For the second element (top right), $3*(-2) + (-2)*6 = -6 - 12 = -18$.3. For the third element (bottom left), $6*0 + 0*2 = 0 + 0 = 0$.4. For the fourth element (bottom right), $6*(-2) + 0*6 = -12 + 0 = -12$.Thus, the product matrix is $\left[\begin{array}{rr} -4 & -18 \ 0 & -12 \end{array}\right]$.

Find the Matrix Product When Possible [3−260][0−226]\left[ \begin{array} { r r } 3 & - 2 \\ 6 & 0 \end{array} \right] \left[ \begin{array} { r r } 0 & - 2 \\ 2 & 6 \end{array} \right][36​−20​][02​−26​]

Find the Matrix Product When Possible $\left[ \begin{array} { r r } 3 & - 2 \\ 6 & 0 \end{array} \right] \left[ \begin{array} { r r } 0 & - 2 \\ 2 & 6 \end{array} \right]$