Solve the problem.
-Find the dimensions of a rectangular enclosure with perimeter $40 \mathrm { yd }$ and area $91 \mathrm { yd } ^ { 2 }$.
A) $13 \mathrm { yd }$ by $7 \mathrm { yd }$
B) $14 \mathrm { yd }$ by $6 \mathrm { yd }$
C) $16 \mathrm { yd }$ by $7 \mathrm { yd }$
D) $15 \mathrm { yd }$ by $6 \mathrm { yd }$

Question

Quizplus · Accepted Answer

The dimensions that satisfy both the perimeter and area conditions are $13 \mathrm { yd }$ by $7 \mathrm { yd }$. The perimeter of a rectangle is given by $2l + 2w = 40$, and the area is $lw = 91$. Only the dimensions $13 \mathrm { yd }$ by $7 \mathrm { yd }$ satisfy both equations, as $2(13) + 2(7) = 40$ and $13 \times 7 = 91$.

Solve the Problem 40yd40 \mathrm { yd }40yd And Area 91yd291 \mathrm { yd } ^ { 2 }91yd2

Solve the Problem $40 \mathrm { yd }$ And Area $91 \mathrm { yd } ^ { 2 }$