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Solve the System to Find W1 and W2 32(W1+W2)=105\frac { \sqrt { 3 } } { 2 } \left( W _ { 1 } + W _ { 2 } \right) = 105

Question 233

Multiple Choice

Solve the system to find W1 and W2.
-Linear systems occur in the design of roof trusses for new homes and buildings. The simplest type of roof truss is a triangle. The truss shown in the figure is used to frame roofs of small buildings. If
A force of 105 pounds is applied at the peak of the truss, then the forces or weights W1 and W2
Exerted parallel to each rafter of the truss are determined by the following linear system of
Equations.  Solve the system to find W<sub>1</sub> and W<sub>2</sub>. -Linear systems occur in the design of roof trusses for new homes and buildings. The simplest type of roof truss is a triangle. The truss shown in the figure is used to frame roofs of small buildings. If A force of 105 pounds is applied at the peak of the truss, then the forces or weights W1 and W2 Exerted parallel to each rafter of the truss are determined by the following linear system of Equations.    \frac { \sqrt { 3 } } { 2 } \left( W _ { 1 } + W _ { 2 } \right)  = 105   W _ { 1 } - W _ { 2 } = 0  A)   W _ { 1 } = 35 \mathrm { lb } ; W _ { 2 } = 35 \mathrm { lb }  B)   W _ { 1 } = 60.62 \mathrm { lb } ; W _ { 2 } = 52.5 \mathrm { lb }  C)   \mathrm { W } _ { 1 } = 60.62 \mathrm { lb } ; \mathrm { W } _ { 2 } = 60.62 \mathrm { lb }  D)   \mathrm { W } _ { 1 } = - 60.62 \mathrm { lb } ; \mathrm { W } _ { 2 } = - 60.62 \mathrm { lb }
32(W1+W2) =105\frac { \sqrt { 3 } } { 2 } \left( W _ { 1 } + W _ { 2 } \right) = 105
W1W2=0W _ { 1 } - W _ { 2 } = 0


A) W1=35lb;W2=35lbW _ { 1 } = 35 \mathrm { lb } ; W _ { 2 } = 35 \mathrm { lb }
B) W1=60.62lb;W2=52.5lbW _ { 1 } = 60.62 \mathrm { lb } ; W _ { 2 } = 52.5 \mathrm { lb }
C) W1=60.62lb;W2=60.62lb\mathrm { W } _ { 1 } = 60.62 \mathrm { lb } ; \mathrm { W } _ { 2 } = 60.62 \mathrm { lb }
D) W1=60.62lb;W2=60.62lb\mathrm { W } _ { 1 } = - 60.62 \mathrm { lb } ; \mathrm { W } _ { 2 } = - 60.62 \mathrm { lb }

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