Use Cramerʹs rule to solve the system of equations. If D = 0, use another method to determine the solution set.
-$$\begin{array} { l }
2 x + 4 y + 8 z = 40 \
x + 2 y + 4 z = - 10 \
x + y + z = - 4
\end{array}$$
A) Cramer's rule does not apply since $D = 0$; $\varnothing$
B) Cramer's rule does not apply since $D = 0 ; \{ ( 2 z - 1 , z + 2 , z ) \}$
C) $\{ ( - 5,3 , - 4 ) \}$
D) $\{ ( - 4 , - 5,3 ) \}$

Question

Use Cramerʹs rule to solve the system of equations. If D = 0, use another method to determine the solution set.
-$$\begin{array} { l } 
2 x + 4 y + 8 z = 40 \
x + 2 y + 4 z = - 10 \
x + y + z = - 4
\end{array}$$
A) Cramer's rule does not apply since $D = 0$; $\varnothing$
B) Cramer's rule does not apply since $D = 0 ; \{ ( 2 z - 1 , z + 2 , z ) \}$
C) $\{ ( - 5,3 , - 4 ) \}$
D) $\{ ( - 4 , - 5,3 ) \}$

Quizplus · Accepted Answer

The Answer of Use Cramerʹs rule to solve the system of equations. If D = 0, use another method to determine the solution set.
-$$\begin{array} { l } 
2 x + 4 y + 8 z = 40 \
x + 2 y + 4 z = - 10 \
x + y + z = - 4
\end{array}$$
A) Cramer's rule does not apply since $D = 0$; $\varnothing$
B) Cramer's rule does not apply since $D = 0 ; \{ ( 2 z - 1 , z + 2 , z ) \}$
C) $\{ ( - 5,3 , - 4 ) \}$
D) $\{ ( - 4 , - 5,3 ) \}$

Use Cramerʹs Rule to Solve the System of Equations 2x+4y+8z=40x+2y+4z=−10x+y+z=−4\begin{array} { l } 2 x + 4 y + 8 z = 40 \\x + 2 y + 4 z = - 10 \\x + y + z = - 4\end{array}2x+4y+8z=40x+2y+4z=−10x+y+z=−4​

Use Cramerʹs Rule to Solve the System of Equations $\begin{array} { l } 2 x + 4 y + 8 z = 40 \\x + 2 y + 4 z = - 10 \\x + y + z = - 4\end{array}$