Find the value of the determinant.
-$\left| \begin{array} { r r r } 6 & 0 & 0 \ 2 & - 4 & 0 \ - 4 & 5 & 3 \end{array} \right|$
A) -82
B) $- 72$
C) 72
D) 62

Question

Quizplus · Accepted Answer

The determinant of a triangular matrix (all elements below or above the main diagonal are zero) is the product of its diagonal elements. Thus, the determinant is $6 \times (-4) \times 3 = -72$.

Find the Value of the Determinant ∣6002−40−453∣\left| \begin{array} { r r r } 6 & 0 & 0 \\ 2 & - 4 & 0 \\ - 4 & 5 & 3 \end{array} \right|​62−4​0−45​003​​

Find the Value of the Determinant $\left| \begin{array} { r r r } 6 & 0 & 0 \\ 2 & - 4 & 0 \\ - 4 & 5 & 3 \end{array} \right|$