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Solve the Problem Using Matrices F{ } ^ { \circ } \mathrm { F }

Question 125

Multiple Choice

Solve the problem using matrices.
-In a study of heat transfer in a grid of wires, the temperature at an exterior node is maintained at a constant value (in F{ } ^ { \circ } \mathrm { F } ) as shown in the figure. When the grid is in thermal equilibrium, the temperature at an interior node is the average of the temperatures at the four adjacent nodes. For instance T1=0+0+300+T24\mathrm { T } _ { 1 } = \frac { 0 + 0 + 300 + \mathrm { T } _ { 2 } } { 4 } , or 4 T1T2=3004 \mathrm {~T} _ { 1 } - \mathrm { T } _ { 2 } = 300 . Find the temperatures T1, T2\mathrm { T } _ { 1 } , \mathrm {~T} _ { 2 } , and T3\mathrm { T } _ { 3 } when the grid is in thermal equilibrium.
 Solve the problem using matrices. -In a study of heat transfer in a grid of wires, the temperature at an exterior node is maintained at a constant value (in  { } ^ { \circ } \mathrm { F }  )  as shown in the figure. When the grid is in thermal equilibrium, the temperature at an interior node is the average of the temperatures at the four adjacent nodes. For instance  \mathrm { T } _ { 1 } = \frac { 0 + 0 + 300 + \mathrm { T } _ { 2 } } { 4 } , or  4 \mathrm {~T} _ { 1 } - \mathrm { T } _ { 2 } = 300 . Find the temperatures  \mathrm { T } _ { 1 } , \mathrm {~T} _ { 2 } , and  \mathrm { T } _ { 3 }  when the grid is in thermal equilibrium.    A)   \mathrm { T } _ { 1 } = \frac { 666 } { 7 } { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 564 } { 7 } { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 3 } = 105 ^ { \circ } \mathrm { F }  B)   \mathrm { T } _ { 1 } = \frac { 766 } { 7 } { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 964 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 3 } = \frac { 430 } { 7 } \circ \mathrm { F }  C)   \mathrm { T } _ { 1 } = \frac { 1352 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 604 } { 7 } \circ { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 3 } = \frac { 655 } { 7 } \circ \mathrm { F }  D)   \mathrm { T } _ { 1 } = \frac { 676 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 604 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 3 } = \frac { 655 } { 14 } \circ \mathrm { F }


A) T1=6667F,T2=5647F,T3=105F\mathrm { T } _ { 1 } = \frac { 666 } { 7 } { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 564 } { 7 } { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 3 } = 105 ^ { \circ } \mathrm { F }
B) T1=7667F,T2=9647F,T3=4307F\mathrm { T } _ { 1 } = \frac { 766 } { 7 } { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 964 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 3 } = \frac { 430 } { 7 } \circ \mathrm { F }
C) T1=13527F,T2=6047F,T3=6557F\mathrm { T } _ { 1 } = \frac { 1352 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 604 } { 7 } \circ { } ^ { \circ } \mathrm { F } , \mathrm { T } _ { 3 } = \frac { 655 } { 7 } \circ \mathrm { F }
D) T1=6767F,T2=6047F,T3=65514F\mathrm { T } _ { 1 } = \frac { 676 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 2 } = \frac { 604 } { 7 } \circ \mathrm { F } , \mathrm { T } _ { 3 } = \frac { 655 } { 14 } \circ \mathrm { F }

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