Solve the problem.
-The perimeter of a rectangle is 38 m. If the width were doubled and the length were increased by 10 m, the perimeter would be 70 m. What are the length and width of the rectangle?
A) Length: 9 m; width: 4 m
B) Length: 13 m; width: 6 m
C) Length: 6 m; width: 13 m
D) Length: 9 m; width: 9 m

Question

Quizplus · Accepted Answer

Let the original length be L and the width be W. The perimeter is given by 2(L + W) = 38, so L + W = 19. If the width is doubled and the length is increased by 10, the new perimeter is 2(2W + L + 10) = 70, simplifying to 2W + L + 10 = 35, so 2W + L = 25. Solving these equations simultaneously, L = 13 and W = 6.

Solve the Problem. -The Perimeter of a Rectangle Is 38 M. If the M