Solve the system in terms of the arbitrary variable x.
-$$x - 3 y + z = 13$$
$3 x - y - z = 3$
A) $\{ ( x , x - 4,3 x + 1 ) \}$
B) $\{ ( 0 , - 4,1 ) \}$
C) $\{ ( x , x - 4,2 x ) \}$
D) $\{ ( x , x - 4,2 x + 1 ) \}$

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The Answer of Solve the system in terms of the arbitrary variable x.
-$$x - 3 y + z = 13$$
$3 x - y - z = 3$
A) $\{ ( x , x - 4,3 x + 1 ) \}$
B) $\{ ( 0 , - 4,1 ) \}$
C) $\{ ( x , x - 4,2 x ) \}$
D) $\{ ( x , x - 4,2 x + 1 ) \}$

Solve the System in Terms of the Arbitrary Variable X x−3y+z=13x - 3 y + z = 13x−3y+z=13

Solve the System in Terms of the Arbitrary Variable X $x - 3 y + z = 13$